Volume Solution 1

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SOLUTION 1: a.) Here are sketches of the base of the solid and the entire solid.

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Here are sketches of a square cross-section at

$x$ , together with it's dimensions.

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The area of the square cross-section is

$A(x)= (edge)^2 = (3- { 1 \over 2 }x)^2$ . Thus the total volume of this static solid is

$Volume = \int_{0}^{6} (3- { 1 \over 2 }x)^2 \ dx$

SOLUTION 1: b.) Here are sketches of the base of the solid and the entire solid.

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Here are sketches of a semi-circular cross-section at

$x$ , together with its radius.

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The area of the semi-circular cross-section is

$A(x)= { 1 \over 2 } \pi r^2 = { 1 \over 2 } \pi ({ 1 \over 2 }(3 - { 1 \over 2 }x))^2$ . Thus the total volume of this static solid is

$Volume = \int_{0}^{6} { 1 \over 2 } \pi \Big({ 1 \over 2 }\Big(3 - { 1 \over 2 }x\Big)\Big)^2 \ dx$

SOLUTION 1: c.) Here are sketches of the base of the solid and the entire solid.

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Here are sketches of a rectangular cross-section at

$x$ , together with its dimensions.

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The area of the rectangular cross-section is

$A(x)= (height)(base) = (5)(3 - { 1 \over 2 }x)$ . Thus the total volume of this static solid is

$Volume = \int_{0}^{6} 5\Big(3 - { 1 \over 2 }x\Big) \ dx$

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