SOLUTION 9: We are given the function $ f(x) = \displaystyle{ x^3 \over 1 - \sqrt{x} } $ and the interval $ [0, 4] $. This function is NOT continuous on the closed interval $ [0, 4] $ since the function is NOT defined at $ x=1$. Thus, the assumptions of the Mean Value Theorem are not satisfied and the Mean Value Theorem does not apply to this example.

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