SOLUTION 9: We are given the function $f(x) = \displaystyle{ x^3 \over 1 - \sqrt{x} }$ and the interval $[0, 4]$. This function is NOT continuous on the closed interval $[0, 4]$ since the function is NOT defined at $x=1$. Thus, the assumptions of the Mean Value Theorem are not satisfied and the Mean Value Theorem does not apply to this example.